SUBJECT ENRICHMENT ACTIVITIES CLASS 4 ENGLISH

 SUBJECT ENRICHMENT ACTIVITIES

CLASS 4 SUBJECT ENGLISH

ACTIVITY 1:  DIFFERENT AND TYPES OF FLOWERS PICTURES  AND THEIR NAMES. 

CRITERIA FOR ASSESSMENT:

★ Creativity

★ vocabulary

★ Spelling

★ Content

ACTIVITY 2-  Dramatization (Tree and a boy)

CRITERIA FOR ASSESSMENT

★ Participation

★Sentence formation

★ Creativity

★ A Content

ACTIVITY 3:  IF I WERE A MANGO TREE CREATIVE WRITING

★ CRITERIA FOR ASSESSMENT

★WRITING SKILL

★CREATIVITY

★ CONTENT

★ SENTENCE FORMATION

★ GRAMMAR

ACTIVITY 4: POEM RECITATION (Books)

CRITERIA FOR ASSESSMENT:

★KNOWING THE POEM 

★Pronunciation

★Gestures

★INTONATION.

ACTIVITY 5: PUPPET SHOW (PINACCHIO)

CRITERIA FOR ASSESSMENT

★ CREATIVITY

☆ PUPPET MAKING

★ Participation

★ Sentence formation

★ Conversation (Dialogue making)

 STATISTICS TEST GRADE 6 

TOTAL = 4 QUESTIONS X 5 MARKS = 20 MARKS

NCERT Class 9 Maths Lab ACTIVITY 10– To draw histogram of heights of students of your class.

 

NCERT Class 9 Maths Lab ACTIVITY 10

– To draw histogram of heights of students of  your class.

Objective
To draw a histogram representing the heights of students using the provided data.

Materials Required

1. Graph paper

2. Geometry box

3. Adhesive

4. Sketch pens

5. Scissors

6. A piece of cardboard

Prerequisite Knowledge

1. Knowledge about collection of data.

2. Concept of histogram.

Step-by-Step Procedure

1. Organize the Data

The given heights are:
157, 159, 170, 144, 156, 163, 164, 154, 163, 164, 158, 152, 165, 157, 171, 164, 172, 162, 150, 170, 151, 157, 170, 159, 163, 201, 168, 171, 160, 191, 164, 170, 182, 154, 167, 165, 171, 168, 188, 176, 160, 184, 184, 177, 165, 166.

Class	a-b	b-c	c -d	d -e	e-f	g-h	i-j
Frequency	f1	f2	f3	f4	f5	f6	f7

2. Determine Class Intervals

Group the heights into equal-sized class intervals (e.g., 140–150, 150–160, 160–170, etc.) and count the number of heights in each interval (frequency).

Class Intervals and Frequency Table:

Height Range (cm)	Frequency
140–150	2
150–160	13
160–170	16
170–180	9
180–190	5
190–200	1
200–210	1

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3. Draw Axes and Scale

• X-Axis: Represent the height intervals (class intervals).

• Y-Axis: Represent the frequency (number of students).

• Use a consistent scale for both axes.

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4. Draw the Histogram

• Draw rectangles (bars) for each class interval.

• The height of each rectangle corresponds to its frequency.

• Ensure there is no gap between rectangles.

• 

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Observations
Graphical Representation

For the classes of equal widths,

The intervals are

• a-b = ………..  140–150: Bar height = 2

• b-c = …………150–160: Bar height = 13

• c-d = ………….. 160–170: Bar height = 16

• d-e = ……….170–180: Bar height = 9

• e-f = ………..180–190: Bar height = 5

• g-h = ………..190–200: Bar height = 1

• i-j = ………..200–210: Bar height = 1

Frequencies are

f1 = ………… 2
f2 = ………..13
f3 = …………. 17
f4 = ………….9
f5 = …………..5

f6 = …………..1

f7 = …………..1

Result
We have drawn a histogram of equal widths and varying widths by using the collected data of the heights of students.

Application
Histograms can be used pictorially in representing large data in a concise form.

Math magic 

In mathematics, no number can be divided by all the numbers between one and ten.
But only one number was considered a mystery by mathematicians around the world. It can even be said that it gave them a shock.
This number was discovered by the unshakable talent of mathematicians of India.
That number: 2520
At first glance, it seems like one of many numbers.
But it is not like that. A number that gave them an insurmountable surprise even by mathematicians around the world!
Because it was a number that could be divided by any number between 1 - 10 - be it an odd number or an even number!
This may give a lot of surprise: it may even seem impossible.
 Look at the mathematical table below:

2520 ÷ 1 = 2520

2520 ÷ 2 = 1260

2520 ÷ 3 = 840

2520 ÷ 4 = 630

2520 ÷ 5 = 504

2520 ÷ 6 = 420

2520 ÷ 7 = 360

2520 ÷ 8 = 315

2520 ÷ 9 = 280

2520 ÷ 10 = 252

The mystery of this has been solved:
[7 × 30 × 12] - This is the multiplication!
According to the calendar followed by our Bharat, an answer has been found for this puzzle.
 The coefficient of this number
Days in a week - 7
Days in a month - 30
Months in a year - 12
*[7 × 30 × 12 = 2520] This is the characteristic and dominance of time.*
(This is the characteristic and dominance of time )
Finally.. that wonderful mind who discovered this -
Mr. Srinivasa Ramanujam.
Let us bow our heads and worship that venerable genius.. great man.
The Great Mind who discovered it was Sri Srinivasa Ramanujam !