Sunday, July 16, 2023

Class 09 To verify the algebraic identity :a3 – b3 = (a – b)(a2 + ab + b2)

 

Activity 10




OBJECTIVE











To verify the algebraic identity :a3 b3 = (a b)(a2 + ab + b2)

 METHOD OF CONSTRUCTION

MATERIAL REQUIRED

Acrylic sheet, sketch pen, glazed papers, scissors, adhesive, cello-tape, coloured papers, cutter.

1.   Make a cuboid of dimensions (a–b) × a × a (b < a), using acrylic sheet and cellotape/adhesive as shown in Fig. 1.

 2.   Make another cuboid of dimensions (a–b) × a × b, using acrylic sheet and cellotape/adhesive as shown in Fig. 2.

 3.   Make one more cuboid of dimensions (a–b) × b × b as shown in Fig. 3.

 4.    Make a cube of dimensions b × b × b using acrylic sheet as shown in Fig. 4.

5.   Arrange the cubes and cuboids made above in Steps (1), (2), (3) and (4) to obtain a solid as shown in Fig. 5, which is a cube of volume a3 cubic units.

Fig. 5

 Fig. 6

 DEMONSTRATION

 Volume of cuboid in Fig. 1 = (a–b) × a × a cubic units.

 Volume of cuboid in Fig. 2 = (a–b) × a × b cubic units.

 Volume of cuboid in Fig. 3 = (a–b) × b × b cubic units.

 Volume of cube in Fig. 4 = b3 cubic units.

 Volume of solid in Fig. 5 = a3 cubic units.

 Removing a cube of size b3 cubic units from the solid in Fig. 5, we obtain a solid as shown in Fig. 6.

 Volume of solid in Fig. 6 = (a–b) a2 + (a–b) ab + (a–b) b2

 =  (a–b) (a2 + ab + b2)

 Therefore, a3 b3 = (a b)(a2 + ab + b2)

OBSERVATION

 On actual measurement:

 a = ..............,        b = ..............,

 So, a3 = ..............,       b3 = .............., (ab) = ..............,    ab = ..............,

 a2  = ..............,      b2 = ..............,

 Therefore, a3 – b3 = (a – b) (a2 + ab + b2).

 APPLICATION

 The identity may be used in simplification/factorisation of algebraic expressions.

Class 09 To verify the algebraic identity (a – b)3 = a3 – b3 – 3(a – b)ab

 Activity 8 















OBJECTIVE

MATERIAL REQUIRED

 

To verify the algebraic identity

Acrylic sheet, coloured papers,

 

(a b)3 = a3 b3 – 3(a b)ab

saw, sketch pens, adhesive, Cello-

 

tape.

 

 

 

METHOD OF CONSTRUCTION

 

 

 1.   Make a cube of side (a – b) units (a > b)using acrylic sheet and cellotape/ adhesive [see Fig. 1].

2.   Make three cuboids each of dimensions (ab) × a × b and one cube of side b units using acrylic sheet and cellotape [see Fig. 2 and Fig. 3].

 Arrange the cubes and cuboids as shown in Fig. 4.

DEMONSTRATION

Volume of the cube of side (a – b) units in Fig. 1 = (a– b)3 Volume of a cuboid in Fig. 2 = (a–b) ab

Volume of three cuboids in Fig. 2 = 3 (a–b) ab Volume of the cube of side b in Fig. 3 = b3

Volume of the solid in Fig. 4 = (a–b)3 + (a–b) ab + (a–b) ab + (a – b) ab + b3

= (a–b)3 + 3(a–b) ab + b3

(1)

 

Also, the solid obtained in Fig. 4 is a cube of side a

Therefore, its volume = a3

(2)

 

From (1) and (2),

 

 

(a–b)3 + 3(a–b) ab + b3 = a3

 

 

or (a–b)3 = a3 b3 – 3ab (a–b).

 

 

Here, volume is in cubic units.

 

 

OBSERVATION

 On actual measurement:

 a = ..............,            b = ..............,       ab = ..............,

 So, a3 = ..............,       ab = ..............,

b3 = ..............,       ab(ab) = ..............,

 3ab (ab) = ..............,     (ab)3 = ..............,

 Therefore, (a–b)3 = a3 – b3 3ab(a–b)

 APPLICATION

 The identity may be used for

 1.   calculating cube of a number expressed as a difference of two convenient numbers

 simplification and factorisation of algebraic expressions.

NOTE

 This identity can also be expressed as : (a b)3 = a3 – 3a2b + 3ab2 b3.

Class 09 To verify the algebraic identity :(a+b)3 = a3 + b3 + 3a2b + 3ab2

 Activity 7




OBJECTIVE                





                                            

To verify the algebraic identity :(a+b)3 = a3 + b3 + 3a2b + 3ab2

 MATERIAL REQUIRED

Acrylic sheet, coloured papers, glazed papers, saw, sketch pen, adhesive, Cello-tape.

METHOD OF CONSTRUCTION

1.   Make a cube of side a units and one more cube of side b units (b < a), using acrylic sheet and cello-tape/adhesive [see Fig. 1 and Fig. 2].

 Similarly, make three cuboids of dimensions a×a×b and three cuboids of dimensions a×b×b [see Fig. 3 and Fig. 4].

3. Arrange the cubes and cuboids as shown in Fig. 5.

DEMONSTRATION

 Volume of the cube of side a = a×a×a = a3, volume of the cube of side b = b3 Volume of the cuboid of dimensions a×a×b = a2b, volume of three such cuboids

=   3a2b

 Volume of the cuboid of dimensions a×b×b = ab2, volume of three such cuboids

=   3ab2

 Solid figure obtained in Fig. 5 is a cube of side (a + b)

 Its volume = (a + b)3

 Therefore, (a+b)3 = a3 + b3 + 3a2b + 3ab2

 Here, volume is in cubic units.

 OBSERVATION

 On actual measurement:

 a = ..............,         b = ............., a3  = ..............,

 So, a3 = ..............,       b3  = ............., a2b = ..............,            3a2b= ..............,

 ab2 = ..............,   3ab2 = ..............,          (a+b)3 = ..............,

 Therefore, (a+b)3 = a3 + b3 +3a2b + 3ab2

 APPLICATION

 The identity may be used for

 1.   calculating cube of a number expressed as the sum of two convenient numbers

 simplification and factorisation of algebraic expressions

ANSWER KEY Class 6 – Ganita Prakash – CHAPTER 6 PERIMETER AND AREA

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