Class 6 Ganita Prakash Chapter 2 Lines and Angles Solutions

๐Ÿ”‘ KEY TO ENJOY LEARNING MATHS

Class 6 Ganita Prakash · Chapter 2
Lines and Angles

Page-wise textbook solutions (pages 13–54) · Every step · Figures · Common mistakes · Tips

✔ Understood 0/83

๐Ÿ—️ Key ideas of this chapter

  • Point — a location (capital letter). Line segment AB — shortest path, two end points. Line — no end points. Ray — one starting point, goes on in one direction (OA ≠ AO).
  • Through one point: infinitely many lines; through two points: exactly one line.
  • Angle — two rays with a common starting point (vertex). Name it with the vertex in the middle: ∠ABC.
  • Size of an angle = amount of turn. Arm length does NOT change the angle.
  • Full turn 360° · straight angle 180° · right angle 90° · acute 0°–90° · obtuse 90°–180° · reflex 180°–360°.
  • Using a protractor: centre on the vertex, one arm on 0°, read the SAME scale.

๐Ÿ“– Textbook Page 14

๐Ÿ“– Page 14Think · Line segment
Mark two points A and B on paper and join them by different routes. What is the shortest route from A to B?
1We can go from A to B along curved, bent or zig-zag paths.
2Every bent path is longer than the straight path.
3The straight path from A to B (including A and B) is the shortest. It is called the line segment AB (or BA).
AB
The dashed curve is longer; the straight segment AB is the shortest path.
✅ Answer: The straight path — the line segment AB — is the shortest route from A to B.
๐Ÿ“– Page 14Think · Line
Can you draw a complete picture of a line? Why?
1A line goes on without end in BOTH directions.
2Paper (or a board) always has an end, so we can never draw all of it.
3So we draw only a part and put arrowheads at both ends to show that it continues.
✅ Answer: No. A line has no end points — it goes on forever in both directions — so only a part of it can be drawn.

๐Ÿ“– Textbook Page 15

๐Ÿ“– Page 15Figure it Out · Q1
Rihan marked one point on paper. How many lines can he draw through it? Sheetal marked two points. How many different lines can she draw through both points?
1Through ONE point we can draw lines in every direction — as many as we like.
2So Rihan can draw countless (infinitely many) lines.
3Through TWO points only one straight line can pass. Any other line would bend or miss one point.
4So Sheetal can draw exactly one line.
one point: many linestwo points: one line
Through one point: as many lines as we like. Through two points: only one.
✅ Answer: Rihan: infinitely many (countless) lines. Sheetal: exactly one line.

๐Ÿ“– Textbook Page 16

๐Ÿ“– Page 16Figure it Out · Q2
Name the line segments in Fig. 2.4. Which of the five marked points are on exactly one of the line segments? Which are on two of the line segments?
LMPQR
Fig. 2.4 (redrawn): a broken path L–M–P–Q–R.
1The path goes L → M → P → Q → R.
2Line segments: LM, MP, PQ and QR.
3L is only on LM and R is only on QR → on exactly one segment.
4M is on LM and MP; P is on MP and PQ; Q is on PQ and QR → on two segments.
✅ Answer: Segments: LM, MP, PQ, QR. On exactly one: L and R. On two: M, P and Q.
๐Ÿ“– Page 16Figure it Out · Q3
Name the rays shown in Fig. 2.5. Is T the starting point of each of these rays?
TNBA
Fig. 2.5 (redrawn).
1One ray starts at T and passes through A → ray TA.
2The other ray starts at T and passes through N and B → ray TN (it can also be called TB).
3Both rays start at T.
✅ Answer: Rays TA and TN (= TB). Yes, T is the starting point of both rays.
⚠️ Common mistake: Writing ray NT or AT. The starting point must be written FIRST.
๐Ÿ“– Page 16Figure it Out · Q4
Draw a rough figure and label it: (a) lines OP and OQ meet at O (b) lines XY and PQ intersect at M (c) line l contains E and F but not D (d) point P lies on AB.
1(a) Draw two lines crossing at O; mark P on one and Q on the other.
2(b) Draw two lines crossing at M; mark X, Y on one line and P, Q on the other.
3(c) Draw a line, name it l, mark E and F on it; mark D away from the line.
4(d) Draw AB and mark P on it between (or beyond) A and B.
PQO(a)YXPQM(b)EFlD(c)APB(d)
(a) lines OP and OQ meet at O · (b) lines XY and PQ cross at M · (c) line l through E and F, D outside · (d) P lies on AB.
✅ Answer: See the four rough figures.
๐Ÿ“– Page 16Figure it Out · Q5
In Fig. 2.6, name: (a) five points (b) a line (c) four rays (d) five line segments.
DEBCO
Fig. 2.6 (redrawn): D, E, O, B lie on one line; one ray goes up from O and one goes through C.
1(a) Points: D, E, O, C, B.
2(b) D, E, O and B lie on one line → line DB (also called line EB, DO, …).
3(c) Rays: OB, OC, OD (same as OE) and ED (it starts at E and goes through D). Others: BD, DB, EB.
4(d) Line segments: DE, EO, OB, OC, DB (others: DO, EB, EO …).
✅ Answer: (a) D, E, O, C, B (b) line DB (c) OB, OC, OD, ED (d) DE, EO, OB, OC, DB — other correct names are possible.
๐Ÿ’ก Tip: The ray going straight up from O has no second point named, so we cannot name it with letters.
๐Ÿ“– Page 16Figure it Out · Q6
Ray OA starts at O and passes through A and B (Fig. 2.7). (a) Can you also name it as OB? Why? (b) Can we write OA as AO? Why or why not?
OBA
Fig. 2.7 (redrawn): ray OA also passes through B.
1(a) A ray is named by its starting point and ANY other point on it. B is on the same ray, so OB names the same ray.
2(b) In AO the starting point would be A, and the ray would go from A towards O and beyond — the opposite direction.
3So OA and AO are different rays.
✅ Answer: (a) Yes — OA and OB are the same ray (same starting point O, same direction). (b) No — AO starts at A and goes the other way.

๐Ÿ“– Textbook Page 17

๐Ÿ“– Page 17Think · Vidya’s book
Vidya opens the cover of her book more and more (Cases 1 to 6). Do you see angles? Which angle is greater — Case 1 or Case 2?
1The spine of the book is the vertex.
2The cover and the pages are the two arms.
3In Case 2 she turns the cover more than in Case 1.
4More turning (rotation) means a bigger angle.
Case 1Case 2Case 3Case 4Case 5
Size of an angle = amount of turn.
✅ Answer: Yes, each case makes an angle. The angle in Case 2 is greater because the cover is turned more.

๐Ÿ“– Textbook Page 18

๐Ÿ“– Page 18Think · Angles around us
Identify the arms and vertex of the angle in (a) a compass or divider (b) a pair of scissors.
1(a) Compass: the two legs are the arms; the joint (hinge) at the top is the vertex.
2(b) Scissors: the two blades are the arms; the screw where the blades are joined is the vertex.
3Opening them wider (turning one arm more) makes a bigger angle.
✅ Answer: Compass: arms = legs, vertex = hinge. Scissors: arms = blades, vertex = the screw.

๐Ÿ“– Textbook Page 19

๐Ÿ“– Page 19Figure it Out · Q1
Find the angles in the pictures (a bicycle, a window grill, a ladder, a bridge). Draw the rays of any one angle and name its vertex.
1In the bicycle frame, the tubes meet at points such as A, B, C, D.
2Take the angle at B: its arms are BC and BD, its vertex is B — this is ∠CBD.
3Other angles: ∠ABD at B, ∠BCD at C, ∠BDA at D.
4In a window grill or ladder, the bars meet at right angles; in a bridge, the slanting bars make acute and obtuse angles.
ABCD
A bicycle frame: one angle is ∠CBD with vertex B (arms BC and BD).
✅ Answer: For example ∠CBD in the bicycle: vertex B, arms BC and BD (many other answers).

๐Ÿ“– Textbook Page 20

๐Ÿ“– Page 20Figure it Out · Q2
Draw and label an angle with arms ST and SR.
1Both arms start at S, so S is the vertex.
2Draw ray ST and ray SR from the same point S.
3The angle is ∠TSR (or ∠RST) — the vertex S is the middle letter.
TRS
∠TSR: vertex S, arms ST and SR.
✅ Answer: ∠TSR (or ∠RST) with vertex S.
๐Ÿ“– Page 20Figure it Out · Q3 (Math Talk)
Explain why ∠APC cannot be labelled as ∠P.
ABCP
Rays PA, PB and PC start at P.
1At P there are three rays: PA, PB and PC.
2So there are three angles with vertex P: ∠APB, ∠BPC and ∠APC.
3‘∠P’ does not tell which of these three we mean.
4We use the single-letter name only when there is just ONE angle at that vertex.
✅ Answer: Because three angles share the vertex P, the name ∠P is not clear — we must use three letters.
๐Ÿ“– Page 20Figure it Out · Q4
Name the angles marked in the given figure (rays TP, TQ and TR from T).
PQRT
Rays TP, TQ and TR start at T; two angles are marked.
1The vertex of all the angles is T (middle letter).
2The arc between TP and TQ marks ∠PTQ.
3The arc between TQ and TR marks ∠QTR.
4Together they make the bigger angle ∠PTR.
PQRT
Angles at T: ∠PTQ, ∠QTR (and the bigger angle ∠PTR).
✅ Answer: ∠PTQ and ∠QTR (and the whole angle ∠PTR).
๐Ÿ“– Page 20Figure it Out · Q5
Mark three points A, B, C not on one line. Draw all lines through pairs of points. How many lines? How many angles can you name using A, B, C?
1Pairs of points: A and B, B and C, C and A.
2So there are 3 lines: AB, BC and CA.
3At A: ∠BAC; at B: ∠ABC; at C: ∠ACB.
4So 3 angles can be named.
ABC
3 points → 3 lines: AB, BC, CA. Angles: ∠BAC, ∠ABC, ∠ACB.
✅ Answer: 3 lines (AB, BC, CA) and 3 angles (∠BAC, ∠ABC, ∠ACB).

๐Ÿ“– Textbook Page 21

๐Ÿ“– Page 21Figure it Out · Q6
Mark four points A, B, C, D so that no three are on one line. Draw all lines through pairs. How many lines? How many angles can you name using A, B, C, D?
1Pairs: AB, AC, AD, BC, BD, CD → 6 lines.
2At each point, three lines meet, giving 3 angles at that point.
3At A: ∠BAC, ∠CAD, ∠BAD. At B: ∠ABC, ∠ABD, ∠CBD.
4At C: ∠ACB, ∠ACD, ∠BCD. At D: ∠ADB, ∠ADC, ∠BDC.
54 points × 3 angles = 12 angles.
ABCD
4 points (no three on one line) → 6 lines: AB, AC, AD, BC, BD, CD.
✅ Answer: 6 lines and 12 angles.
⚠️ Common mistake: Counting only the 4 corner angles of ABCD. The diagonals AC and BD make more angles at every corner.
๐Ÿ“– Page 21Math Talk · Comparing angles
Here are some angles. Label each one. How will you compare them?
Angle 1Angle 2Angle 3Angle 4
Four angles in different positions. Trace one and place it on another (vertex on vertex, one arm on one arm) to compare.
1Label each angle with three letters, the vertex in the middle (for example ∠ABC).
2The angles point in different directions, so it is hard to compare them just by looking.
3Trace one angle on tracing paper and place it on another so that the vertices match and one arm lies on one arm.
4The angle whose second arm lies outside is bigger. (In this figure the order from smallest is Angle 3, Angle 1, Angle 2, Angle 4.)
✅ Answer: Label them and compare by superimposing (placing one on top of the other). Here: Angle 3 (50°) < Angle 1 (75°) < Angle 2 (105°) < Angle 4 (130°).

๐Ÿ“– Textbook Page 22

๐Ÿ“– Page 22Think · Equal angles
∠AOB and ∠XOY are placed one on top of the other: OA lies on OX and OB lies on OY. Which angle is greater?
1When superimposed, the vertices match.
2Both arms also lie exactly on top of each other.
3So the same amount of turn is needed in both angles.
OABOXYO (O)
When the vertex and both arms match, the angles are equal.
✅ Answer: Neither — the angles are equal.

๐Ÿ“– Textbook Page 23

๐Ÿ“– Page 23Math Talk
Where else do we use superimposition (placing one thing on another) to compare?
1Comparing the lengths of two pencils by keeping them side by side with ends together.
2Checking if two coins, stamps or tiles are the same size and shape.
3A tailor places one cloth piece on another to cut the same shape.
✅ Answer: To compare lengths, sizes and shapes — pencils, coins, tiles, cloth pieces, leaves, etc.
๐Ÿ“– Page 23Figure it Out · Q1
Fold a rectangular sheet of paper and draw a line on the fold. Name and compare the angles between the fold and the sides of the paper. Make different angles by folding. Which is the largest and smallest angle you made?
1If the fold is parallel to a side, it meets the other sides at right angles — all the angles are equal (90°).
2If the fold is slanting, at each side it makes one smaller (acute) angle and one larger (obtuse) angle.
3The two angles on the same side together make a straight angle (180°).
4The more slanting the fold, the smaller the acute angle and the larger the obtuse angle.
✅ Answer: A straight-across fold gives four right angles; a slanting fold gives acute and obtuse pairs that add up to 180°. (Your largest/smallest angles depend on your folds.)
๐Ÿ“– Page 23Figure it Out · Q2
In each case, which angle is greater and why? (a) ∠AOB or ∠XOY (b) ∠AOB or ∠XOB (c) ∠XOB or ∠XOC
AXYOBC
Rays OA, OX, OY and OB (with C) start at O.
1(a) Rays OX and OY lie inside ∠AOB, so ∠XOY is a part of ∠AOB → ∠AOB is greater.
2(b) Ray OX lies inside ∠AOB, so ∠XOB is a part of ∠AOB → ∠AOB is greater.
3(c) B and C are on the same ray from O, so ∠XOB and ∠XOC are the same angle → they are equal.
AXYOBC
B and C lie on the same ray from O, so ∠XOB and ∠XOC are the same angle.
✅ Answer: (a) ∠AOB (b) ∠AOB (c) equal.
⚠️ Common mistake: Thinking ∠XOC is bigger because OC is longer. The length of the arms does NOT change the angle.
๐Ÿ“– Page 23Figure it Out · Q3 (Math Talk)
Which angle is greater: ∠XOY or ∠AOB? Give reasons.
XAYBO
Which is greater: ∠XOY or ∠AOB?
1Trace ∠AOB and place it on ∠XOY so that O is on O and OB lies along OY.
2Then OA falls inside ∠XOY (between OY and OX).
3So ∠AOB fits inside ∠XOY. (By measuring: ∠XOY ≈ 110°, ∠AOB ≈ 54°.)
XAYBO
∠XOY ≈ 110° (blue) and ∠AOB ≈ 54° (red). ∠XOY is greater.
✅ Answer: ∠XOY is greater.

๐Ÿ“– Textbook Page 25

๐Ÿ“– Page 25Think · Cranes
Two cranes argue about who opens its mouth wider. Using a transparent circle (centre on the vertex), which crane makes the bigger angle?
1Put the circle on Crane 1’s angle with its centre on the vertex. Mark A and B where the arms cut the circle.
2Move the circle to Crane 2: centre on the vertex and one arm through A.
3Crane 2’s other arm crosses the circle at Y, beyond B.
4So Crane 2’s mouth is turned more.
ABCrane 1OABYCrane 2O
Place the circle with its centre on the vertex and one arm through A. Crane 2’s upper arm passes OUTSIDE B (at Y), so Crane 2 opens wider.
✅ Answer: Crane 2 makes the bigger angle.

๐Ÿ“– Textbook Page 26

๐Ÿ“– Page 26Think · Passing through a slit
Which rotating arm can pass through the angle-shaped slit? Does the length of the arms matter?
1If the slit’s angle is bigger than the arms’ angle, the arms do not fit.
2If the slit’s angle is smaller, the arms do not fit either.
3Only arms with exactly the same angle as the slit pass through.
4Longer or shorter arms do not matter (as long as they fit in the slit) — only the angle matters.
✅ Answer: Only the rotating arm whose angle is EQUAL to the slit’s angle passes through. Length does not matter.

๐Ÿ“– Textbook Page 27

๐Ÿ“– Page 27Challenge
A boy cuts the straws of a rotating arm shorter to ‘reduce the angle’. Has the angle become smaller?
1Cutting the straws makes the arms shorter.
2But the amount of turn between the arms is the same.
3The size of an angle does not depend on the length of its arms.
✅ Answer: No. The angle is still the same; only the arms are shorter.
⚠️ Common mistake: Thinking that longer arms make a bigger angle.

๐Ÿ“– Textbook Page 28

๐Ÿ“– Page 28Math Talk · Straight angle
Is it possible to draw ray OC so that the two angles ∠AOC and ∠COB of the straight angle AOB are equal? How?
1Mark the straight angle AOB on the edge of a paper.
2Fold the paper so that OB lies exactly on OA (the fold passes through O).
3The crease OC divides the straight angle into two angles that lie exactly on top of each other when folded.
4So ∠AOC = ∠COB. Each of them is a right angle.
AOBC
Fold so that OB lies on OA: the crease OC splits the straight angle into two equal right angles (90° each).
✅ Answer: Yes. Fold OB onto OA; the crease OC makes two equal angles — two right angles.

๐Ÿ“– Textbook Page 29

๐Ÿ“– Page 29Think
A straight angle is half of a full turn. How much of a full turn is a right angle?
1A straight angle = ½ turn.
2A right angle is half of a straight angle.
3½ of ½ turn = ¼ turn.
✅ Answer: A right angle is a quarter (¼) of a full turn.
๐Ÿ“– Page 29Figure it Out · Q1
How many right angles do the windows of your classroom contain? Do you see other right angles in your classroom?
1A rectangular window frame has 4 corners → 4 right angles.
2If it has bars, every place where a bar meets the frame or another bar makes more right angles (often 4 at each crossing).
3Other right angles: corners of the blackboard, door, desk top, books, tiles, walls and floor.
✅ Answer: A plain rectangular window has 4 right angles (more if it has bars). Doors, boards, books and tiles also have right angles.

๐Ÿ“– Textbook Page 30

๐Ÿ“– Page 30Figure it Out · Q2
Join A to other grid points by a straight line to get a straight angle with AB. What are all the different ways?
1A straight angle means the new line continues the line BA straight on, beyond A.
2Left grid (AB is flat): the points to the left of A in the same row → 3 ways.
3Right grid (AB slants down): the points up-left of A on the same slant → 2 ways.
123AB12AB
Straight angle: the new line must continue BA straight on, beyond A. Left grid: 3 ways. Right grid: 2 ways.
✅ Answer: Left grid: 3 ways. Right grid: 2 ways (all on the line BA extended beyond A).
๐Ÿ“– Page 30Figure it Out · Q3
Now join A to other grid points to get a right angle with AB. What are all the different ways?
1A right angle divides the straight angle CAB (C on BA extended) into two equal parts.
2Left grid: the line must go straight up or straight down from A: 2 points above + 3 points below = 5 ways.
3Right grid: AB goes 1 right, 1 down each step. The line at right angles goes 1 right, 1 up (or 1 left, 1 down): 2 points up-right + 2 points down-left = 4 ways.
12345AB1234AB
Right angle: the new line must go straight up or down from A, square to AB. Left grid: 5 ways. Right grid: 4 ways.
✅ Answer: Left grid: 5 ways. Right grid: 4 ways.

๐Ÿ“– Textbook Page 31

๐Ÿ“– Page 31Figure it Out · Q4
Make a slanting crease on paper. Then make another crease perpendicular to it. (a) How many right angles do you have? Justify. (b) Describe how you folded.
1Fold any slanting crease and open it.
2Fold the paper again so that the slanting crease lies exactly on top of itself (one part of the crease falls on the other part).
3Press to make the new crease, then open.
4(a) The new crease divides each straight angle on the slanting crease into two equal parts, so all four angles are right angles.
5They are exact right angles because, when folded, the two parts lay exactly on top of each other.
✅ Answer: (a) 4 right angles. (b) Fold the slanting crease onto itself, press, and unfold.
๐Ÿ“– Page 31Figure it Out · Q1 (Classifying)
Identify acute, right, obtuse and straight angles in the previous figures.
1Acute (less than a right angle): Vidya’s book in Cases 1–2, the cranes’ beaks, the slanting window bars, Fig. 2.4 at Q.
2Right: the folds of paper, the window frames, the grid answers with a right angle.
3Obtuse (between right and straight): Vidya’s book in Case 4, ∠XOY on page 23, the open scissors when wide.
4Straight: Vidya’s book opened flat on the table (Case 5), ∠AOB in Fig. 2.11.
✅ Answer: See the examples in the steps.
๐Ÿ“– Page 31Figure it Out · Q2
Make a few acute angles and a few obtuse angles. Draw them in different orientations.
1Acute: draw two arms that open less than an ‘L’ — for example 30°, 50°, 80°.
2Obtuse: arms that open more than an ‘L’ but less than a straight line — for example 100°, 135°, 160°.
3Turn your notebook and draw some with the base arm slanting or pointing left — the angle stays the same type.
30°acute80°acute55°acute110°obtuse150°obtuse130°obtuse
Different orientations — the type depends only on the opening.
✅ Answer: See the examples: acute angles (30°, 50°, 80°) and obtuse angles (100°, 135°, 160°).

๐Ÿ“– Textbook Page 32

๐Ÿ“– Page 32Figure it Out · Q3
Acute means ‘sharp’ and obtuse means ‘blunt’. Why do you think these words were chosen?
1An acute angle has a narrow opening, so its corner is pointed — like the tip of a needle or a knife (sharp).
2An obtuse angle opens wide, so its corner is flat and not pointed (blunt).
✅ Answer: Acute angles look sharp and pointed; obtuse angles look blunt and wide.
๐Ÿ“– Page 32Figure it Out · Q4
Find the number of acute angles in each figure (a triangle, then the triangle with its midpoints joined, and so on). What will be the next figure and how many acute angles will it have? Do you see a pattern?
Figure 1Figure 2Figure 3
How many acute angles are there in each figure?
1Figure 1: a triangle with 3 angles of 60° → 3 acute angles.
2Figure 2: 3 new points (midpoints). At each one, the lines make 3 angles of 60° on one side → 3 × 3 = 9 more. Total 3 + 9 = 12.
3Figure 3: the middle triangle is divided again → 3 new points × 3 = 9 more. Total 21.
4Next figure: divide the newest middle triangle again → 21 + 9 = 30.
3 acute angles12 acute angles21 acute anglesnext: 30
Each new figure adds 3 new points, each with 3 angles of 60° → 9 more acute angles: 3, 12, 21, 30, …
✅ Answer: 3, 12, 21; the next figure has 30 acute angles. The number goes up by 9 each time.
๐Ÿ’ก Tip: The 120° and 180° angles at the midpoints are not acute, so do not count them.

๐Ÿ“– Textbook Page 33

๐Ÿ“– Page 33Think · Measures of special angles
What is the measure of a full turn, a straight angle and a right angle in degrees?
1A full turn is divided into 360 equal parts of 1° → 360°.
2A straight angle is half a turn → 360° ÷ 2 = 180°.
3A right angle is half a straight angle → 180° ÷ 2 = 90°.
✅ Answer: Full turn = 360°, straight angle = 180°, right angle = 90°.

๐Ÿ“– Textbook Page 34

๐Ÿ“– Page 34Think · Dividing a circle
A circle is divided into 1, 2, 3, 4, 5, 6, 8, 9, 10 and 12 equal parts. Write the degree measure of each angle.
1Each angle = 360° ÷ number of parts.
2360 ÷ 1 = 360, ÷ 2 = 180, ÷ 3 = 120, ÷ 4 = 90, ÷ 5 = 72.
3360 ÷ 6 = 60, ÷ 8 = 45, ÷ 9 = 40, ÷ 10 = 36, ÷ 12 = 30.
1 part: 360°2 parts: 180°3 parts: 120°4 parts: 90°5 parts: 72°6 parts: 60°8 parts: 45°9 parts: 40°10 parts: 36°12 parts: 30°
360° ÷ number of equal parts = each angle.
✅ Answer: 360°, 180°, 120°, 90°, 72°, 60°, 45°, 40°, 36°, 30°.
๐Ÿ’ก Tip: 360 can be divided exactly by 1, 2, 3, 4, 5, 6, 8, 9, 10 and 12 — that is one reason we use 360°.

๐Ÿ“– Textbook Page 35

๐Ÿ“– Page 35Figure it Out · Q1
Using the unlabelled protractor (centre at A), write the measures of (a) ∠KAL (b) ∠WAL (c) ∠TAK.
KLWTA
An unlabelled protractor turned on its side, with its centre at A.
1Count the 1° marks between the arms (use the 10° long marks to count in 10s).
2(a) Between AK and AL there are 3 long gaps → 30°.
3(b) AL is 10° above the middle line and AW is 40° below it → 10 + 40 = 50°.
4(c) AK is 40° above the middle line and AT is 80° below it → 40 + 80 = 120°.
✅ Answer: (a) ∠KAL = 30° (b) ∠WAL = 50° (c) ∠TAK = 120°

๐Ÿ“– Textbook Page 36

๐Ÿ“– Page 36Think · Labelled protractor
Why does a protractor have two sets of numbers (one increasing from right to left and the other from left to right)?
1An angle may have one arm pointing right or pointing left.
2If the base arm points right, we start from 0 on the right and use that scale.
3If the base arm points left, we start from 0 on the left and use the other scale.
4So we can measure without turning the protractor around.
✅ Answer: So that we can start counting from 0° on either side — whichever side the base arm lies.
๐Ÿ“– Page 36Think · Name the angles
Name the different angles in the figure (rays OP, OQ, OR, OS, OT, OU on a protractor) and write their measures.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180PQRSTUO
1Read each ray on the inner scale (0° at P): OQ → 35°, OR → 95°, OS → 125°, OT → 160°, OU → 180°.
2Angles from OP: ∠POQ = 35°, ∠POR = 95°, ∠POS = 125°, ∠POT = 160°, ∠POU = 180°.
3Angles from OQ (subtract 35): ∠QOR = 60°, ∠QOS = 90°, ∠QOT = 125°, ∠QOU = 145°.
4Angles from OR (subtract 95): ∠ROS = 30°, ∠ROT = 65°, ∠ROU = 85°.
5∠SOT = 160 − 125 = 35°, ∠SOU = 55°, ∠TOU = 20°.
✅ Answer: 15 angles: ∠POQ 35°, ∠POR 95°, ∠POS 125°, ∠POT 160°, ∠POU 180°, ∠QOR 60°, ∠QOS 90°, ∠QOT 125°, ∠QOU 145°, ∠ROS 30°, ∠ROT 65°, ∠ROU 85°, ∠SOT 35°, ∠SOU 55°, ∠TOU 20°.

๐Ÿ“– Textbook Page 37

๐Ÿ“– Page 37Think · ∠TOS by subtraction
OT and OS pass through 20 and 55 on the outer scale. What is ∠TOS? Can subtraction be used?
1The outer scale counts from OU (0°).
2OT is at 20° and OS is at 55°.
3∠TOS = 55° − 20° = 35°.
✅ Answer: ∠TOS = 35° — yes, subtract the two readings on the SAME scale.
๐Ÿ“– Page 37Think · ∠AOB
The protractor’s centre is on O and OB passes through 0°. What is the degree measure of ∠AOB?
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180BAO
1OB is on 0° of the inner scale, so read the inner scale.
2OA passes through 80 on the inner scale.
✅ Answer: ∠AOB = 80°
⚠️ Common mistake: Reading 100° from the outer scale. Use the scale that starts at 0° on the arm OB.

๐Ÿ“– Textbook Page 38

๐Ÿ“– Page 38Make your own protractor
Fill in the blanks: half a turn = ½ of ___ = 180°; ¼ turn = ¼ of 360° = ___; ¼ turn = ½ of 180° = ___.
1Half a turn = ½ of 360° = 180°.
2¼ of 360° = 360 ÷ 4 = 90°.
3½ of 180° = 90°.
✅ Answer: 360°; 90°; 90°

๐Ÿ“– Textbook Page 39

๐Ÿ“– Page 39Make your own protractor · Q4–Q5
When folded again, the angle is ⅛ of a turn = ¼ of 180° = ½ of 90° = ___. Continuing with another half fold, we get an angle of ___.
1⅛ of 360° = 45°; ¼ of 180° = 45°; ½ of 90° = 45°.
2Folding once more halves 45°: 45° ÷ 2 = 22.5° (22½°).
AB22.5°C45°D67.5°E90°F112.5°G135°H157.5°I0°180°O
Paper protractor: every fold halves the angle, so the 8 equal angles are each 180° ÷ 8 = 22.5°.
✅ Answer: 45° and then 22.5°.

๐Ÿ“– Textbook Page 40

๐Ÿ“– Page 40Think
In Fig. 2.19, ∠AOB = ∠BOC = ∠COD = … = ∠HOI = ___. Why?
1The straight angle AOI (180°) was folded in half 3 times.
2180° → 90° → 45° → 22.5°: the 8 angles are all equal.
3180° ÷ 8 = 22.5°.
✅ Answer: 22.5° each, because the 8 equal angles come from halving 180° three times.
๐Ÿ“– Page 40Figure it Out · Q1
Find the degree measures of the three angles (∠IHJ in each figure) using your protractor.
(i)(ii)(iii)
The three angles (redrawn).
1Place the centre on the vertex H and one arm on the 0° line.
2Read where the other arm crosses the same scale.
45°(i) 45°25°(ii) 25°110°(iii) 110°
Measured values.
✅ Answer: (i) 45° (ii) 25° (iii) 110°
๐Ÿ’ก Tip: Your paper protractor marks only 22.5°, 45°, 67.5° … so use a standard protractor for 25° and 110°.
๐Ÿ“– Page 40Figure it Out · Q2
Find the degree measures of different angles in your classroom using your protractor.
1Corner of a book, door or board: 90°.
2A door opened a little: about 30°–60°.
3The legs of a slanting chair back or an open laptop screen: about 100°–120°.
✅ Answer: Answers depend on your classroom; corners of rectangular objects measure 90°.

๐Ÿ“– Textbook Page 41

๐Ÿ“– Page 41Figure it Out · Q3
Find the degree measures of the two angles given (∠IHJ). Check if your paper protractor can be used here!
(i)(ii)
1Measure each angle with a standard protractor (centre on H, one arm on 0°).
2First angle ≈ 40°, second angle ≈ 115°.
3The paper protractor only has 0°, 22.5°, 45°, 67.5°, 90°, 112.5°, … so it cannot give 40° or 115° exactly (only roughly).
40°(i) 40°115°(ii) 115°
✅ Answer: About 40° and 115°. The paper protractor can only give a rough idea here.
๐Ÿ“– Page 41Figure it Out · Q4
How can you find the degree measure of the angle given below (a reflex angle) using a protractor?
1A protractor reads only up to 180°.
2Measure the smaller angle between the two arms: it is 100°.
3The marked angle goes the long way round: full turn − smaller angle.
4360° − 100° = 260°.
✅ Answer: Measure the smaller angle (100°) and subtract it from 360°: the angle is 260°.
๐Ÿ’ก Tip: Another way: extend one arm to make a straight angle (180°) and measure the extra part (80°): 180° + 80° = 260°.
๐Ÿ“– Page 41Figure it Out · Q5 (a)–(b)
Measure and write the degree measures of angles (a) and (b).
(a)(b)
1Place the centre on the vertex and the bottom arm on 0°.
2(a) The other arm is at 80°.
3(b) The other arm is at 120°.
80°(a) 80°120°(b) 120°
✅ Answer: (a) 80° (b) 120°

๐Ÿ“– Textbook Page 42

๐Ÿ“– Page 42Figure it Out · Q5 (c)–(f)
Measure and write the degree measures of angles (c), (d), (e) and (f).
(c)(d)(e)(f)
1Turn the protractor so that one arm lies on the 0° line and the centre is on the vertex.
2(c) 60° (d) 130° (e) 130° (f) 60°.
60°(c) 60°130°(d) 130°130°(e) 130°60°(f) 60°
✅ Answer: (c) 60° (d) 130° (e) 130° (f) 60°
๐Ÿ“– Page 42Figure it Out · Q6
Find the degree measures of ∠BXE, ∠CXE, ∠AXB and ∠BXC.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180EABCX
1XE is on 0° of the inner scale: XB reads 115° and XC reads 85°.
2∠BXE = 115°, ∠CXE = 85°.
3∠AXB = 180° − 115° = 65° (or read 65° on the outer scale).
4∠BXC = 115° − 85° = 30°.
✅ Answer: ∠BXE = 115°, ∠CXE = 85°, ∠AXB = 65°, ∠BXC = 30°
๐Ÿ“– Page 42Figure it Out · Q7
Find the degree measures of ∠PQR, ∠PQS and ∠PQT.
PRSTQ
1Place the centre on Q with QP on the 0° line.
2QR is 45° from QP, QS is 100° from QP and QT is 150° from QP.
✅ Answer: ∠PQR = 45°, ∠PQS = 100°, ∠PQT = 150°

๐Ÿ“– Textbook Page 43

๐Ÿ“– Page 43Figure it Out · Q8
Make the paper craft (a dog face), unfold it, draw lines on the creases and measure the angles formed.
1The first fold along a diagonal of a square makes 45° angles with the sides.
2Folding the triangle in half makes a crease at 90° to the long side.
3Folding the corners down makes more 45° and 90° angles; some creases meet at 135° (= 90° + 45°).
✅ Answer: Most angles you measure will be 45°, 90°, 135° or 180°.
๐Ÿ“– Page 43Figure it Out · Q9
Measure the three angles of each triangle in Fig. 2.21 and add them. What do you get? Make a conjecture.
1Triangle (a): 40° + 75° + 65° = 180°.
2Triangle (b): 70° + 55° + 55° = 180°.
3Triangle (c): 35° + 40° + 105° = 180°.
4Every time the total is 180° (or very close, because of small measuring errors).
ABC40°75°65°
(a) 40° + 75° + 65° = 180°
CBA55°55°70°
(b) 55° + 55° + 70° = 180°
ABC35°40°105°
(c) 35° + 40° + 105° = 180°
✅ Answer: The three angles of any triangle add up to 180°.
๐Ÿ’ก Tip: We will learn WHY this is always true in a later class.

๐Ÿ“– Textbook Page 44

๐Ÿ“– Page 44Mind the Mistake · ∠U
A student measured ∠U = 35°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180U
The student’s reading: ∠U = 35°.
1Mistake: The protractor’s base line is not along either arm. The student read only from the base to one arm.
2Correct method: Turn the protractor so that one arm lies on the 0° line, then read the other arm.
3Measured correctly, ∠U ≈ 60°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180U
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠U = 60°.
✅ Answer: The reading 35° is wrong; ∠U ≈ 60°.
๐Ÿ“– Page 44Mind the Mistake · ∠V
A student measured ∠V = 80°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180V
The student’s reading: ∠V = 80°.
1Mistake: The protractor is tilted: neither arm lies along the 0° line, so the reading is wrong.
2Correct method: Keep the centre on V and line up one arm with the 0° line before reading.
3Measured correctly, ∠V ≈ 70°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180V
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠V = 70°.
✅ Answer: The reading 80° is wrong; ∠V ≈ 70°.
๐Ÿ“– Page 44Mind the Mistake · ∠W
A student measured ∠W = 70°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180W
The student’s reading: ∠W = 70°.
1Mistake: The vertex W is not at the centre of the protractor — the student put the centre at the end of an arm.
2Correct method: Always place the centre point exactly on the vertex.
3Measured correctly, ∠W ≈ 75°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180W
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠W = 75°.
✅ Answer: The reading 70° is wrong; ∠W ≈ 75°.
๐Ÿ“– Page 44Mind the Mistake · ∠X
A student measured ∠X = 150°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180X
The student’s reading: ∠X = 150°.
1Mistake: One arm is on 0° of the inner scale but the reading was taken from the outer scale.
2Correct method: Read the scale that starts at 0° on your arm. The angle is clearly acute, so 150° cannot be right.
3Measured correctly, ∠X ≈ 30°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180X
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠X = 30°.
✅ Answer: The reading 150° is wrong; ∠X ≈ 30°.
๐Ÿ“– Page 44Mind the Mistake · ∠Y
A student measured ∠Y = 120°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180Y
The student’s reading: ∠Y = 120°.
1Mistake: The protractor stands upright, so neither arm lies on its base line.
2Correct method: Turn it so that the base lies along one arm, then read the other arm.
3Measured correctly, ∠Y ≈ 145°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180Y
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠Y = 145°.
✅ Answer: The reading 120° is wrong; ∠Y ≈ 145°.
๐Ÿ“– Page 44Mind the Mistake · ∠Z
A student measured ∠Z = 85°. Find the mistake in using the protractor and correct it.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180Z
The student’s reading: ∠Z = 85°.
1Mistake: The protractor is upside down; the angle opens below the base where there is no scale.
2Correct method: Turn the protractor over so that the angle lies inside the half-circle.
3Measured correctly, ∠Z ≈ 105°.
18001701016020150301404013050120601107010080909080100701106012050130401403015020160101700180Z
Correct way: centre on the vertex, one arm on 0°, read the same scale → ∠Z = 105°.
✅ Answer: The reading 85° is wrong; ∠Z ≈ 105°.

๐Ÿ“– Textbook Page 45

๐Ÿ“– Page 45Figure it Out · Q1 (a)
At 1 o’clock the angle between the hands of a clock is 30°. Why?
1The 12 numbers divide the full turn (360°) into 12 equal parts.
2Each part = 360° ÷ 12 = 30°.
3At 1 o’clock the minute hand is at 12 and the hour hand at 1 → one part apart.
1212345678910111 o’clock: 30°
The 12 numbers split the full turn (360°) into 12 equal parts of 30° each.
✅ Answer: Because one ‘hour gap’ on the clock face is 360° ÷ 12 = 30°.
๐Ÿ“– Page 45Figure it Out · Q1 (b)
What will be the angle between the hands at 2 o’clock? At 4 o’clock? At 6 o’clock?
12 o’clock: 2 gaps × 30° = 60°.
24 o’clock: 4 gaps × 30° = 120°.
36 o’clock: 6 gaps × 30° = 180° (a straight angle).
12123456789101160°121234567891011120°121234567891011180°
The 12 numbers split the full turn (360°) into 12 equal parts of 30° each.
✅ Answer: 60°, 120° and 180°.
๐Ÿ“– Page 45Figure it Out · Q1 (c)
Explore other angles made by the hands of a clock.
13 o’clock and 9 o’clock: 90° (right angles).
25 o’clock: 150°; 7 o’clock: 150° the short way round (210° the long way).
312 o’clock: 0° — the hands are together.
4At 6:00 the hands make a straight angle.
✅ Answer: For example 3:00 → 90°, 5:00 → 150°, 9:00 → 90°, 12:00 → 0°.
๐Ÿ“– Page 45Figure it Out · Q2
Can the amount a door is opened be shown by an angle? What are the vertex and the arms?
1Yes. The door turns about its hinges.
2Vertex: the hinge line (seen from above it is a point).
3Arms: the door in its closed position (the door frame/wall line) and the door in its open position.
4The wider the door is opened, the bigger the angle.
✅ Answer: Yes. Vertex = hinge; arms = closed position and open position of the door.
๐Ÿ“– Page 45Figure it Out · Q3
Vidya swings from a greater starting angle to go faster. Where is the angle?
1The vertex is the point on the branch where the ropes are tied.
2One arm is the rope hanging straight down (at rest).
3The other arm is the rope at the starting position.
4A bigger angle between these two positions gives more speed.
✅ Answer: Between the rope hanging straight down and the rope at the starting position; the vertex is where the rope is tied.

๐Ÿ“– Textbook Page 46

๐Ÿ“– Page 46Figure it Out · Q4
A toy has slanting slabs. Can angles describe the slopes? What are the arms? Which arm is visible and which is not?
1Yes — a steeper slab makes a bigger angle and the ball rolls faster.
2One arm is the slab itself (visible).
3The other arm is the horizontal (flat, level) line through the lower end of the slab — it is not drawn, so we cannot see it.
4The vertex is the lower end where the slab meets the side.
✅ Answer: Yes. Arms: the slab (visible) and the horizontal line (not visible).
๐Ÿ“– Page 46Figure it Out · Q5
An insect is shown and then rotated. Can angles describe the rotation? What are the arms and vertex?
1Yes. Use the horizontal line touching the insect.
2One arm: the direction the insect faced first (along the horizontal line).
3Other arm: the direction it faces after turning.
4Vertex: the point about which it turned.
5The ladybird turns from lying flat to standing up — a turn of 90° (a right angle).
✅ Answer: Yes. Arms = old and new directions of the insect, vertex = the turning point; for example the ladybird turned 90°.

๐Ÿ“– Textbook Page 49

๐Ÿ“– Page 49Figure it Out · Q1
In Fig. 2.23, list all the angles possible. Guess their measures, then measure them with a protractor.
ABPRCDLS
Fig. 2.23 (redrawn): the two long lines are parallel; AC, PL and RS cross both of them.
1Angles that can be named with the letters: ∠CAB at A; ∠ACD at C; ∠APL and ∠LPB at P; ∠PRS and ∠SRB at R; ∠PLC and ∠PLS at L; ∠RSC at S.
2Measured: ∠CAB = 105°, ∠ACD = 75°.
3∠APL = 80°, ∠LPB = 100°; ∠PLC = 100°, ∠PLS = 80°.
4∠SRB = 80°, ∠PRS = 100°; ∠RSC = 80°.
5Note: the two angles at the same point on a straight line always add up to 180°.
ABPRCDLS105°75°80°80°100°80°
Fig. 2.23 (redrawn): the two long lines are parallel; AC, PL and RS cross both of them. Some of the angles are marked.
✅ Answer: ∠CAB 105°, ∠ACD 75°, ∠APL 80°, ∠LPB 100°, ∠PLC 100°, ∠PLS 80°, ∠PRS 100°, ∠SRB 80°, ∠RSC 80° (in our redrawn figure).

๐Ÿ“– Textbook Page 50

๐Ÿ“– Page 50Figure it Out · Q2
Use a protractor to draw angles of (a) 110° (b) 40° (c) 75° (d) 112° (e) 134°.
1Draw a base ray, for example IN.
2Put the centre of the protractor on I and the 0° line along IN.
3Count up from 0° on that scale to the required number and make a small dot.
4Remove the protractor and join I to the dot with a ruler. Label the angle.
110°(a)40°(b)75°(c)112°(d)134°(e)
Angles drawn with a protractor.
✅ Answer: See the drawn angles.
๐Ÿ“– Page 50Figure it Out · Q3
Draw an angle with the same degree measure as the given angle ∠IHJ. Write down your steps.
JIH
1Measure the given angle: centre on H, HJ on 0°; HI reads 115°.
2Draw a ray QR.
3Place the centre on Q and QR along 0°.
4Mark a dot at 115° on the same scale.
5Join Q to the dot: the new angle is 115°.
✅ Answer: The angle measures 115°; copy it using the steps.

๐Ÿ“– Textbook Page 51

๐Ÿ“– Page 51Figure it Out · Q1 (a)
Join A to other grid points to get an acute angle with AB.
1Acute means less than a right angle.
2Pick a point so that the new line opens less than an ‘L’ from AB.
3Left grid: for example A to the point 2 right and 2 up (45°).
4Right grid: for example A to the point 3 to the right in the same row (45°).
ABAB
Examples of acute angles (less than a right angle) — many other answers are possible.
✅ Answer: Many answers — any point that makes an opening smaller than a right angle.

๐Ÿ“– Textbook Page 52

๐Ÿ“– Page 52Figure it Out · Q1 (b)
Join A to other grid points to get an obtuse angle with AB.
1Obtuse means more than a right angle but less than a straight angle.
2Left grid: for example A to the point 2 left and 2 up (135°).
3Right grid: for example A to the point 2 left and 1 down (about 108°).
ABAB
Examples of obtuse angles (between a right angle and a straight angle).
✅ Answer: Many answers — any point that opens wider than an ‘L’ but not straight.
๐Ÿ“– Page 52Figure it Out · Q1 (c)
Join A to other grid points to get a reflex angle with AB.
1Every pair of lines from A makes two angles: a smaller one and a reflex one (the long way round).
2Draw any line from A (not along AB).
3Mark the BIG angle — the one more than 180° — with a curve.
4For example, with the 45° acute angle, the reflex angle is 360° − 45° = 315°.
ABAB
Reflex angle: the SAME lines as an acute angle, but we measure the big angle the long way round (more than 180°).
✅ Answer: Any line works — mark the larger (outside) angle, e.g. 315°.
๐Ÿ“– Page 52Figure it Out · Q2
Use a protractor to find the measure of each angle and classify it: (a) ∠PTR (b) ∠PTQ (c) ∠PTW (d) ∠WTP (the reflex angle).
PRQWT
Rays TP, TR, TQ and TW start at T.
1Read each ray with TW on the 0° line: TQ 40°, TR 70°, TP 100°.
2(a) ∠PTR = 100° − 70° = 30° → acute.
3(b) ∠PTQ = 100° − 40° = 60° → acute.
4(c) ∠PTW = 100° → obtuse.
5(d) Reflex ∠WTP = 360° − 100° = 260° → reflex.
PRQWT
∠PTR = 30°, ∠PTQ = 60°, ∠PTW = 100°, reflex ∠WTP = 260°.
✅ Answer: (a) 30° acute (b) 60° acute (c) 100° obtuse (d) 260° reflex

๐Ÿ“– Textbook Page 53

๐Ÿ“– Page 53Let’s Explore
In the figure ∠TER = 80° and ∠SER = 90°. What is ∠BET? What is ∠SET?
80°BRSTE
∠TER = 80°, ∠SER = 90°; B, E and R lie on a straight line.
1∠REB is a straight angle = 180°.
2∠BET = 180° − 80° = 100°.
3∠SET = ∠SER − ∠TER = 90° − 80° = 10°.
80°BRSTE
∠BET = 180° − 80° = 100° and ∠SET = 90° − 80° = 10°.
✅ Answer: ∠BET = 100° and ∠SET = 10°.
๐Ÿ“– Page 53Figure it Out · Q1
Draw angles with degree measures (a) 140° (b) 82° (c) 195° (d) 70° (e) 35°.
1(a), (b), (d), (e): draw a base ray, put the protractor’s centre on the vertex and 0° on the ray, mark the number, and join.
2(c) 195° is more than 180°: 195° − 180° = 15°.
3Draw a straight line through the vertex, then draw an arm 15° below the straight line on the other side.
4Or: 360° − 195° = 165°; draw a 165° angle and mark the OUTSIDE (reflex) angle.
140°(a)82°(b)195°(c)70°(d)35°(e)
195° is drawn the long way round.
✅ Answer: See the drawn angles; 195° is drawn as a reflex angle (360° − 165°).
๐Ÿ“– Page 53Figure it Out · Q2
Estimate each angle (a)–(f), then measure it with a protractor and classify it.
(a)(b)(c)(d)(e)(f)
1Compare each angle with a right angle (an ‘L’) to estimate it.
2(a) 45° acute (b) 165° obtuse (c) 120° obtuse.
3(d) 35° acute (e) 100° obtuse (f) 350° reflex (the small gap is only 10°).
45°45° acute165°165° obtuse120°120° obtuse35°35° acute100°100° obtuse350°350° reflex
✅ Answer: (a) 45° acute (b) 165° obtuse (c) 120° obtuse (d) 35° acute (e) 100° obtuse (f) 350° reflex
๐Ÿ“– Page 53Figure it Out · Q3
Make any figure with three acute angles, one right angle and two obtuse angles.
1One easy figure is a zig-zag line with 6 corners.
2Make the corners 40°, 60° and 70° (acute), 90° (right), 120° and 150° (obtuse).
3Check each corner with a protractor.
40°120°60°90°150°70°
Green = acute (40°, 60°, 70°), blue = right (90°), purple = obtuse (120°, 150°).
✅ Answer: See the zig-zag figure (many other figures are possible).
๐Ÿ“– Page 53Figure it Out · Q4
Draw the letter ‘M’ so that the angles on the sides are 40° each and the angle in the middle is 60°.
1Draw the two middle strokes first, meeting at the bottom with an angle of 60° (each 30° from the vertical).
2At each top corner, draw the outer leg so that it makes 40° with the middle stroke.
3The outer legs then lean outwards a little (10° from the vertical).
60°40°40°
Letter M: each side angle 40°, middle angle 60° (the outer legs lean out by 10°).
✅ Answer: See the drawn letter M.
๐Ÿ“– Page 53Figure it Out · Q5
Draw the letter ‘Y’ so that the three angles formed are 150°, 60° and 150°.
1Draw the stem straight down from the centre point.
2Draw one arm at 150° from the stem on the left and one at 150° on the right.
3The angle between the two arms is 360° − 150° − 150° = 60°.
60°150°150°
Letter Y: 150° + 60° + 150° = 360° (a full turn round the centre).
✅ Answer: See the drawn letter Y (150° + 60° + 150° = 360°).

๐Ÿ“– Textbook Page 54

๐Ÿ“– Page 54Figure it Out · Q6
The Ashoka Chakra has 24 spokes. What is the angle between two neighbouring spokes? What is the largest acute angle formed between two spokes?
1The 24 spokes divide the full turn into 24 equal angles.
2Each angle = 360° ÷ 24 = 15°.
3Angles between spokes are 15°, 30°, 45°, 60°, 75°, 90°, …
4The largest one below 90° is 75° (5 gaps).
15°75°
24 equal angles round the centre: 360° ÷ 24 = 15°. Five gaps make 75°, the largest acute angle.
✅ Answer: 15° between neighbouring spokes; the largest acute angle is 75°.
๐Ÿ“– Page 54Figure it Out · Q7 (Puzzle)
I am an acute angle. Doubling, tripling or quadrupling me still gives an acute angle, but 5 times me is obtuse. What can I be?
14 times the angle is acute → 4 × angle < 90° → angle < 22.5°.
25 times the angle is obtuse → 5 × angle > 90° → angle > 18°.
3(5 × angle is also less than 180°, which is true.)
4So the angle is between 18° and 22.5°.
✅ Answer: Any angle more than 18° and less than 22.5°: in whole degrees 19°, 20°, 21° or 22°.
⚠️ Common mistake: Including 18°: 5 × 18° = 90° is a right angle, not obtuse.

๐ŸŒ Where do we use angles?

  • Clocks (30° between numbers), doors, swings, slopes of roads and slides.
  • Builders and carpenters check right angles; engineers use angles for bridges and roofs.
  • Sports: the angle of a cricket bat or a football kick; navigation and directions.

๐Ÿš€ Link to higher classes

  • Class 6: Playing with Constructions and Symmetry use angles again.
  • Class 7: Parallel and Intersecting Lines; angle sum of a triangle (180°).
๐Ÿ”‘ keytoenjoylearningmaths.blogspot.com · Solutions written in our own words, based on NCERT Ganita Prakash Class 6 (Grade 6)

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