Sunday, July 16, 2023

Class 09 To verify experimentally the different criteria for congruency of triangles using triangle cut-outs.

 Activity 14

 

 




 

OBJECTIVE                                                                  


 

To verify experimentally the different criteria for congruency of triangles using triangle cut-outs.


   MATERIAL REQUIRED

 

Cardboard, scissors, cutter, white paper, geometry box, pencil/sketch pens, coloured glazed papers.

 


METHOD OF CONSTRUCTION

 

1.   Take a cardboard of a convenient size and paste a white paper on it.

 

2.   Make a pair of triangles ABC and DEF in which AB = DE, BC = EF, AC = DF on a glazed paper and cut them out [see Fig. 1].

 

Make a pair of triangles GHI, JKL in which GH = JK, GI = JL,G =J on a glazed paper and cut them out [see Fig. 2].

4.   Make a pair of triangles PQR, STU in which QR = TU,Q =T,R =U on a glazed paper and cut them out [see Fig. 3].

 

5.    Make two right triangles XYZ, LMN in which hypotenuse YZ = hypotenuse MN and XZ = LN on a glazed paper and cut them out [see Fig. 4].

 

 

 

 

 

 

 

 

 

 

 

 

 

Fig. 3

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Fig. 4

 

DEMONSTRATION

 

1.   Superpose DABC on DDEF and see whether one triangle covers the other triangle or not by suitable arrangement. See that Ξ”ABC covers Ξ”DEF completely only under the correspondence AD, BE, CF. So, Ξ”ABC ≅ Ξ”DEF, if AB = DE, BC = EF and AC = DF.

 

This is SSS criterion for congruency.

2.   Similarly, establish Ξ”GHI ≅ Ξ”JKL if GH = JK.G =J and GI = JL. This is SAS criterion for congruency.

 

3.   Establish Ξ”PQR ≅ Ξ”STU, if QR = TU,Q =T andR =U. This is ASA criterion for congruency.

 

4.   In the same way, Ξ”STU ≅ Ξ”LMN, if hypotenuse YZ = hypotenuse MN and XZ = LN.

 

This is RHS criterion for right triangles.

OBSERVATION

 

 

 

On actual measurement :

 

 

In Ξ”ABC and Ξ”DEF,

 

 

 

AB = DE = ...................

,

BC = EF = ...................

,

AC = DF = ...................

,

A = ...................

,

D = ...................

,

B = ...................

,

C = ...................

,

F = ....................

Therefore, Ξ”ABC ≅ Ξ”DEF.

 

 

2. In Ξ”GHI and Ξ”JKL,

 

 

GH = JK = ...................

,

GI = JL = ....................

,

KL= ...................

,

G = ...................

,

H = ...................

,

K = ...................

,

L = ....................

 

 

Therefore, Ξ”GHI ≅ Ξ”JKL.

 

 

3. In Ξ”PQR and Ξ”STU,

 

 

QR = TU = ...................

,

PQ = ...................

,

PR = ...................

,

SU = ....................

Q =T = ...................

,

R =U = ...................

,

E = ...................,

 

 

 

 

 

 

HI =

...................,

J =

...................,

I =

...................,

 

 

 

 

 

 

ST = ...................,

 

S = ...................,

 

P = ....................

4. In Ξ”XYZ and Ξ”LMN, hypotenuse YZ = hypotenuse MN = .............

 

XZ=LN=

...................,

XY = ...................

,

 

 

LM = ...................

,

X=L=90°

 

 

 

Y = ...................

,

M = ...................

,

Z = ...................

,

N = ...................

,

 

 

 

 

Therefore, Ξ”XYZ ≅ Ξ”LMN.

 

APPLICATION

 

These criteria are useful in solving a number of problems in geometry.

 

These criteria are also useful in solving some practical problems such as finding width of a river without crossing it.

Clas 09 the vertically opposite angles are equal (ii) the sum of two adjacent angles is 180ΒΊ (iii) the sum of all the four angles is 360ΒΊ.

 

Activity 13




OBJECTIVE                                                                   

To verify experimentally that if two lines intersect, then

 (i)       the vertically opposite angles are equal

 (ii)        the sum of two adjacent angles is 180ΒΊ

 (iii)      the sum of all the four angles is 360ΒΊ.

  MATERIAL REQUIRED

Two transparent strips marked as AB and CD, a full protractor, a nail, cardboard, white paper, etc.

METHOD OF CONSTRUCTION

1.   Take a cardboard of a convenient size and paste a white paper on it.

2.   Paste a full protractor (0° to 360ΒΊ) on the cardboard, as shown in Fig. 1.

3.   Mark the centre of the protractor as O.

4.   Make a hole in the middle of each transparent strip containing two intersecting lines.

5.   Now fix both the strips at O by putting a nail as shown in Fig. 1.

DEMONSTRATION

1.   Observe the adjacent angles and the vertically opposite angles formed in different positions of the strips.

 2.   Compare vertically opposite angles formed by the two lines in the strips in different positions.

 3.   Check the relationship between the vertically opposite angles.

 4.   Check that the vertically opposite anglesAOD,COB,COA andBOD are equal.

 5.   Compare the pairs of adjacent angles and check thatCOA +DOA= 180ΒΊ, etc.

 6.   Find the sum of all the four angles formed at the point O and see that the sum is equal to 360ΒΊ.

 OBSERVATION

 On actual measurement of angles in one position of the strips : 

1.

AOD = .................

,AOC = ...................

 

 

 

COB = .................

,BOD = .................

 

 

Therefore,AOD =COB andAOC = ............

(vertically opposite angles).

2.

AOC +AOD = .............

,AOC +BOC =

...................,

 

COB +BOD = ...................

 

 

 

AOD +BOD = ...................

(Linear pairs).

 

 

3.

AOD +AOC +COB +BOD = ....................

(angles formed at a point).

 APPLICATION

 These properties are used in solving many geometrical problems.

Class 09 To find a hidden picture by plotting and joining the various points with given coordinates in a plane.

 Activity 12




OBJECTIVE                                                                    

To find a hidden picture by plotting and joining the various points with given coordinates in a plane.

 MATERIAL REQUIRED

Cardboard, white paper, cutter, adhesive, graph paper/squared paper, geometry box, pencil.

METHOD OF CONSTRUCTION

1.   Take a cardboard of a convenient size and paste a white paper on it.

2.   Take a graph paper and paste it on the white paper.

3.   Draw two rectangular axes XOX and YOY as shown in Fig. 1.

4.   Plot the points A, B, C, ... with given coordinates (a, b), (c, d), (e, f), ..., respectively as shown in Fig. 2.

Join the points in a given order say ABCD.....A [see Fig. 3]

DEMONSTRATION

By joining the points as per given instructions, a ‘hidden’ picture of an ‘aeroplane’ is formed.

OBSERVATION

In Fig. 3:

Coordinates of points A, B, C, D, .......................

are ........, ........, ........, ........, ........, ........, ........

Hidden picture is of ______________.

APPLICATION

This activity is useful in understanding the plotting of points in a cartesian plane which in turn may be useful in preparing the road maps, seating plan in the classroom, etc.

Class 09 To find the values of abscissca and ordinates of various points given in a cartesian plane.

 Activity 11




  OBJECTIVE                                                                   

To find the values of abscissca and ordinates of various points given in a cartesian plane.

  MATERIAL REQUIRED

 

Cardboard, white paper, graph paper with various given points, geometry box, pen/pencil.

 METHOD OF CONSTRUCTION

 1.   Take a cardboard of a convenient size and paste a white paper on it.

 2.    Paste the given graph paper alongwith various points drawn on it [see Fig. 1].

 3.   Look at the graph paper and the points whose abcissae and ordinates are to be found.

 DEMONSTRATION

 To find abscissa and ordinate of a point, say A, draw perpendiculars AM and AN from A to x-axis and y-axis, respectively. Then abscissa of A is OM and ordinate of A is ON. Here, OM = 2 and AM = ON = 9. The point A is in first quadrant. Coordinates of A are (2, 9)

OBSERVATION

 

Point

Abscissa

Ordinate

Quadrant

Coordinates

 

B

 

C

 

...

 

...

 

...

 

...

 

 

PRECAUTION

 

 

Fig. 1

The students should be careful

 

APPLICATION

while reading the coordinates,

 

 

This activity is helpful in locating the position

otherwise the location of the

 

object will differ.

 

of a particular city/place or country on map

ANSWER KEY Class 6 – Ganita Prakash – CHAPTER 6 PERIMETER AND AREA

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