Class 08 Activity – Algebraic Expressions4

 Class 08 Activity – Algebraic Expressions4

Objective: 

To solve linear equations in one variable by activity method.

Materials Required: 

Thick paper strips of two colours (red and green) of dimensions x cm x 1 cm, thick paper squares of two colours (red and green) of dimensions 1 cm x 1 cm.

Procedure: 

Let us solve the linear equation in one variable 5x-3 = 3x + 5.

Let us represent the linear equation 5x-3 = 3x + 5 using strips and squares.

2. Subtracting (removing) three green strips from L.H.S. as well as from R.H.S.

5x-3x-3 = 3x-3x + 5

2x-3 = 5

The strips and squares in fig. 2 represent 2x-3 = 5

3. Now add three green squares on L.H.S. as well on R.H.S.

(b)2x-3+ 3 = 5 + 3

2x = 8

x = 4

Observations:

Now if we substitute x = 4 in the given linear equation 

5x-3 = 3x + 5, 

we get 5x4-3 = 3 x 4 + 5

20-3 = 12 + 5

17 = 17

Hence, x = 4 is the required solution of the given linear equation which has been solved experimentally and verified.