ACTIVITY1 - LINES AND ANGLES
Objective:
To verify that if two parallel lines are cut by a transversal, then each pair of corresponding angles are equal, by paper cutting and pasting.
Materials Required:
White sheets of paper, colour pencils, geometry box, a pair of scissors, glue stick etc.
Procedure:
1. On a white sheet of paper, draw a pair of parallel lines AB and CD. Also, draw a transversal EF, cutting AB and CD at P and Q respectively. Mark the angles as shown in the figure. Mark a point O somewhere in the middle of PQ.
2. Cut the figure along the dotted lines to get four angular cut outs as shown below.
3. Paste the angular cutout ∠DQO over ∠BPE such that Q coincides with P and QD falls along PB.
4. Similarly, paste the angular cut outs ∠DQF, ∠CQF and ∠CQO over ∠BPO, ∠APO and ∠APE resp., such that in each case Q coincides with P and one arm of each angle falls along one arm of the corresponding angle.
Observations:
In figure1, AB ∥ CD and EF is Transversal. So, (∠EPB, ∠DQO), (∠BPO, ∠DQF), (∠APE, ∠CQP) and (∠APQ, ∠CQF ) are four pairs of corresponding angles.
2. In figure, we see that if vertex Q of ∠DQO coincides with the vertex P of ∠BPE and QD falls along PB, then QO falls along PE, i.e., DQO completely overlaps BPE. So, ∠DQO = ∠BPE.
3. Similarly, in fig, we see that ∠DQF, ∠CQF and ∠CQO completely overlap ∠BPO, ∠APO and ∠APE resp.,
So, ∠DQF = ∠BPO, ∠CQF = ∠APO and ∠CQO = ∠APE
Conclusion :
From the above activity, we can say that if two parallel lines are cut by a transversal, then each pair of corresponding angles are equal.
Do yourself:
Verify the above property by drawing a pair of parallel lines which are 5 cm apart.
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