Activity 9
To verify the algebraic identity : a3 + b3 = (a + b) (a2 – ab + b2)
MATERIAL REQUIRED
Acrylic sheet, glazed papers,
saw, adhesive, cellotape, coloured papers, sketch pen, etc.
METHOD OF CONSTRUCTION
1. Make a cube of side a units and another cube of side b units as shown in Fig. 1 and Fig. 2 by using acrylic sheet and cellotape/adhesive.
2. Make a cuboid of dimensions a × a × b [see Fig. 3].
3. Make a cuboid of dimensions a × b × b [see Fig. 4].
Arrange these cubes and cuboids as shown in Fig.
DEMONSTRATION
Volume of cube in Fig. 1 = a3
Volume of cube in Fig. 2 = b3
Volume of cuboid in Fig. 3 = a2b
Volume of cuboid in Fig. 4 = ab2
Volume of solid in Fig. 5 = a3+b3 + a2b + ab2 = (a+b) (a2 + b2)
Removing cuboids of volumes a2b and ab2, i.e.,Fig. 6
ab (a + b) from solid
obtained in Fig. 5, we get the solid in Fig. 6.
Volume of solid in Fig. 6 = a3 + b3.
Therefore, a3 + b3 = (a+b) (a2 + b2) – ab (a + b)
= (a+b) (a2 + b2 – ab)
Here, volumes are in cubic units.
OBSERVATION
On actual measurement:
a = .............., b = ..............,
So, a3 = .............., b3 = .............., (a+b) = .............., (a+b)a2 = ..............,
(a+b) b2 = .............., a2b = .............., ab2 = ..............,
ab (a+b) = ..............,
Therefore, a3 + b3 = (a + b) (a2 + b2 – ab).
APPLICATION
The identity may be used in simplification and factorisation of algebraic expressions.
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