Class 09 To find experimental probability of each outcome of a die when it is thrown a large number of times.

 

Activity 34

OBJECTIVE

MATERIAL REQUIRED

To find experimental probability of each

Die, note book, pen.

outcome of a die when it is thrown a large

 

number of times.

 

METHOD OF CONSTRUCTION

 

 1.    Divide the whole class in ten groups say G1, G2, G3, ..., G10 of a suitable size.

 2.   Allow each group to throw a die 100 times and ask them to note down the observations, i.e., the number of times the outcomes 1, 2, 3, 4, 5 or 6 come up.

 3.    Count the number of times 1 has appeared in all the groups. Denote it by a. Similarly, count the number of times each of 2, 3, 4, 5 and 6 has appeared.

 Denote them by b, c, d, e and f respectively.

 4.   Find the probability of each outcome ‘E’ using the formula :

P(E)=

Number of times an outcome occured

 Total number of trials

 DEMONSTRATION

 1.   There are 10 groups and each group throws a die 100 times. So, the total number of trials is 1000.

 2.   Total number of times 1 has appeared is a 

Therefore, experimental probability of 1 is

P(1)=

 

a

 

 

 

 

 

 

 

 

 

 

 

1000

 

 

 

 

 

Similarly, experimental probability of 2 is P(2) =

b

 

, of 3 is P(3) =

c

 

,

 

of 4 is

P(4)=

 

d

,

 

 

 

1000

 

 

 

 

 

 

 

 

 

of 5 is

P(5)=

 

e

,

of 6 is P (6) =

f

 

1000

 

 

 

 

 

1000

 

OBSERVATION

 Fill in the results of your experiment in the following table: 

Outcome\

 

Number of times a number comes up on a die

Total

 

Group

 

1

 

2

 

 

3

 

 

 

4

 

5

 

6

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

G1

 

----

 

----

 

 

----

 

 

 

----

 

----

 

----

100

 

G2

 

----

 

----

 

 

----

 

 

 

----

 

----

 

----

100

 

G3

 

----

 

----

 

 

----

 

 

 

----

 

----

 

----

100

 

.

 

 

.

 

.

 

 

.

 

 

 

.

 

.

 

.

 

 

.

 

 

.

 

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.

 

.

 

 

G10

 

----

 

----

 

 

----

 

 

 

----

 

----

 

----

100

 

Total

 

a = ----

 

 

b = ----

 

c = ----

d = ----

 

 

e = ----

f = ----

1000

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Therefore,

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

.......

 

 

.......

 

.......

 

 

 

.......

 

 

 

 

P(1)=

 

 

, P(2)=

 

 

,

P(3)=

 

 

,

P(4)=

 

 

,

 

 

 

 

 

1000

 

 

1000

 

 

 

1000

 

 

 

1000

 

 

 

 

 

 

 

.......

 

 

.......

 

 

 

 

 

 

 

 

 

 

 

 

 

 

P(5)=

 

 

, P(6)=

 

 

.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

1000

 

 

 

 

 

 

 

 

 

 

 

 

 

1000

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 APPLICATION

Concept of probability is used by several statistical institutions to estimate/ predict next action based on available data.

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